Let us assume shape of well is like a solid circular cylinder
Radius of cylinder, r = 2/2 = 1m
Depth(height) of well, h = 14m
Volume of right circular cylinder, V’ = πr2 h
= \(π\times{1}^2\times14\)---------(I)
Given that,
length of embankment, l = 40 cm
Let width of the embankment be x m
Volume of the embankment, V’’ = πr2 h
= π ((1+x)2 – 1)2 x 0.4 -----------(II)
Since well is spread evenly to form the embankment, so their volumes, V’ = V’’
⇒ π × 14 = π ((1+x)2 – 1)2 x 0.4
⇒ x = 5 m
∴ Height of the embankment, x = 5cm