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A conical flask is full of water. The flask has base-radius r and height h. The water is poured into a cylindrical flask of base-radius rm. Find the height of water in the cylindrical flask.

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Volume of conical flask =\(\frac{1}3\)πr2

∵ Volume of water in cylindrical flask = volume of conical flask

∴ \(\pi(rm)^2h' = \frac{1}3\pi r^2h\)

⇒ h' = \(\frac{1}3(\frac{r}{rm})^2h\)

⇒ h' = \(\frac{h}{3m^2}\)

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