Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
1.1k views
in Mathematics by (15.0k points)

Use the identity (x + a) (x + b) = x2 + (a + b)x + ab to find the following products. 

(i) (x + 3) (x + 7) (ii) (4x +5) (4x + 1)

(iii) (4x − 5) (4x − 1) (iv) (4x + 5) (4x − 1)

1 Answer

+1 vote
by (24.9k points)
selected by
 
Best answer

(i) (x + 3) (x + 7) 

= x2 + (3 + 7) x + (3) (7) 

= x2 + 10x + 21

(ii) (4x + 5) (4x + 1) 

= (4x)2 + (5 + 1) (4x) + (5) (1) 

= 16x2 + 24x + 5

(iii) (4x - 5) (4x - 1)

= (4x)2 + [ (-5) + (-1) ] (4x) + (5) (-1)

= 16x2 + 16x -5

(iv) (4x + 5) (4x - 1) 

= (4x)2 + [ (5) + (-1) ] (4x) + (5) (-1)

=16x2 + 16x − 5

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...