(i) (x + 3) (x + 7)
= x2 + (3 + 7) x + (3) (7)
= x2 + 10x + 21
(ii) (4x + 5) (4x + 1)
= (4x)2 + (5 + 1) (4x) + (5) (1)
= 16x2 + 24x + 5
(iii) (4x - 5) (4x - 1)
= (4x)2 + [ (-5) + (-1) ] (4x) + (5) (-1)
= 16x2 + 16x -5
(iv) (4x + 5) (4x - 1)
= (4x)2 + [ (5) + (-1) ] (4x) + (5) (-1)
=16x2 + 16x − 5