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Show that the points whose position vectors are  \(\vec a = 4\hat i-3\hat j+\hat k,\)  \(\vec b=2\hat i-4\hat j+5k,\)  \(\vec c=\hat i-\hat j\)  form a right triangle.

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Given Data:

\(\vec a = 4\hat i-3\hat j+\hat k\) 

\(\vec b=2\hat i-4\hat j+5k\) 

\(\vec c=\hat i-\hat j\) 

= -2 × 3 + (-1) × (-2) + 1 × 4

= -6 + 2 + 4

Angle A right angle, ABC is right angle triangle.

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