Height of the cylindrical bucket = 32 cm
Radius of the cylindrical bucket = 18 cm
Volume of the bucket = πr2 h
= π × 182 × 32 cm3
= π x 18 x 18 x 32
Height of the conical heap = 24 cm
Let Radius of the conical heap = r cm
Volume of conical heap = \(\frac{1}{3}πr^2h\)
= \(\frac{1}{3}π\times{r}^2\times24\) cub.cm
Volume of conical heap=Volume of cylindrical bucket