Given
radius of Cylindrical base = 20 m
Height of Cylindrical part (h) = 4.2
Volume of Cylindrical = ….(1)
V1 = π(20)2 4.2
= 5280 m3
Volume 0f Cone = \(\frac{1}3πr^2h\)
Height of conical part (h) = 2.1 m …..(2)
V2 = \(\frac{π}3\) (20)2 (2.1)
= 880 m3
Volume of tent (v) = V1 + V2
V = 5280 + 880
= 6160 m3