Given:
radius of circular cone (r) = 60 cm
Height of a cone (l) = 120 cm
Volume of a cone = \(\frac{1} 3\) πr2 l
= \(\frac{1} 3\) π(60)2(120) cm …….. (1)
Volume of a hemisphere = \(\frac{2}3\)πr2
Given radius of hemisphere = 60 cm
= \(\frac{2}3\)π(60)3……………. (2)
Radius of cylinder (r) = 60 cm
Height of cylinder (h) = 180 cm
Volume of cylinder = πr2h
= π(60)2(180) cm3 ……… (3)
Volume of water left in cylinder = eq.(3) – eq.(1) + eq.(2)
= \(\frac{1} 3\)π(60)2(120) - [\(\frac{2} 3\)π(60)3 + π(60)2(180)]
= 113.1 cm3 = 1.131m3