Given,
h = 24 cm, r’ = 15 cm and r’’ = 5 cm
Let slant height be l
Slant height, l = \(\sqrt{(r' - r")^2 + h^2}\)
⇒ l = \(\sqrt{(15 - 5)^2 + 24^2}\)
⇒ l = 26 cm
Total surface area of the frustum = π(r’ + r’’)l+ πr’’2
= π(15 + 5)(26) + π (5)2
= 1711.3 cm2
Cost of metal sheet used at the rate of Rs. 10 per 100 cm2
= \(\frac{1711.3}{100}\times10\)
= Rs 171