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The circumference of a circle exceeds the diameter by 16.8 cm. Find the circumference of the circle.

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Given : 

The circumference of a circle exceeds the diameter by 16.8 cm.

To find : 

The circumference of the circle.

Solution : 

Let diameter of circle = x cm 

So, 

acc. to given condition 

Circumference = x+16.8 cm 

Circumference of circle is 2πr. 

⇒ 2πr = x + 16.8 

Diameter = 2r

⇒ \(\frac{22}7\times{x} = x + 16.8\) 

⇒ \(\frac{22}7{x} -x = 16.8\)

⇒ \(\frac{22x - 7x}7= 16.8\)

⇒ \(\frac{15x}7= 16.8\)

⇒ 15 x = 16.8 × 7

⇒15 x = 117.6

⇒ x = \(\frac{117.6}{15}\)

⇒ x = 7.84

Circumference= x + 16.8 (x = 2r) 

Circumference = 7.84 + 16.8 = 24.64 cm

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