Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
266 views
in Trigonometry by (30.5k points)
closed by

The value of sin2 29° + sin2 61° is 

A. 1 

B. 0 

C. 2 sin2 29° 

D. 2 cos2 61

1 Answer

+1 vote
by (30.3k points)
selected by
 
Best answer

To find: sin2 29° + sin261° 

Consider sin2 29° + sin261° 

∵ 29 = 90 – 61 

∴ sin2 29° + sin261° = sin2 (90° – 61°) + sin2 61° 

Now, as sin (90° – θ) = cos θ 

⇒ sin2 29° + sin261° = sin2 (90° – 61°) + sin2 61° 

= cos2 61° + sin2 61° 

= 1 [sin2θ + cos2θ = 1]

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...