Sarthaks Test
0 votes
1.4k views
in Physics by (8.6k points)

A uniform disc of radius R, is resting on a table on its rim.The coefficient of friction between disc and table is μ (Fig 7.12). Now the disc is pulled with a force F as shown in the figure. What is the maximum value of F for which the disc rolls without slipping ?

1 Answer

0 votes
by (13.6k points)
selected by
 
Best answer

Let the accelaration of the centre of mass of disc be ‘a’, then

Ma = F-f

The angular accelaration of the disc is a = a/R. (if there is no sliding). 

Then

((1/2)MR2)α = Rf

⇒Ma = 2f

Thus, f = F/3. Since there is no sliding,

⇒ f ≤ μmg

⇒ F ≤ μMg.

 

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...