Given,
Perimeter of sector = 27.2 m
Radius of sector = 5.6 m
= \(\frac{θ}{360}\times2πr + 2r\) = 27.2
= \(\frac{θ}{360}\times2πr \) = 27.2 - 11.2
= \(\frac{θ}{360}\) = \(\frac{16}{2πr}\) (Equation first)
Area of sector = \(\frac{θ}{360}\timesπr^2 \) (Equation second)
Put value of \(\frac{θ}{360}\) from equation first to equation second
= \(\frac{16}{2πr}\timesπr^2\) = \(\frac{16\times5.6}2\) = 44.8 m2
