Question

Calculate 

1. The number of molecules present in 1 g of water. 

2. The volume of 0.2 mole of sulphur dioxide at STP.

Answer 1

1. Number of moles in 1 g water = \(\frac{1}{8}\)

∴ No. of molecules in 1 g water

= \(\frac{1\times6.022\times10^{23}}{18}\) = 3.35 x 10²²

2. Volume of 0.2 mol SO₂ at STP = 0.2 × 22.4 litre 

= 4.48 litre