Question

A bead sliding on a wire A moves to C through B as shown in the figure. The bead at A has a speed of 200cms

1. what is speed at B?

2. To what height will it rise before it returns?

3. Why the ball moves up even after reaching the bottom most point B?

Answer 1

1. mgh = 1/2 mv²

m × 10 × 0.8 = 1/2 mv²

V² = 2 × 10 × 0.8

V = \(\sqrt{2×10×0.8}\)

V = 4 m/s.

2. 80 cm (if friction is neglected).

3. when the ball reaches at B, the potential energy is converted into kinetic energy. Due to this kinetic energy the ball raises to the point c.