Radius of circle = 14 cm
Angle = 60°
Area of sector = \(\frac{θ}{360}πr^2\)
= \(\frac{60}{360}π\times14\times14\) = \(\frac{98}3π\) = 102.57 cm2
Area of triangle OAB = \(\frac{1}2r^2\) sin θ
= \(\frac{1}{2}\times14\times14\times{sin}θ\)
= \(\frac{1}{2}\times14\times14\times\frac{\sqrt3}2\)
= \(49\sqrt3\) = 84.77 cm2
So,
Area of minor segment = 102.57 – 84.77 = 17.80 cm2