Given points are:
⇒ A = (1, 2, 3)
⇒ B = (4, 5, 7)
⇒ C = (–4, 3, –6)
⇒ D = (2, 9, 2)
Let us assume the direction ratios for line AB be (r1, r2, r3) and CD be (r4, r5, r6)
We know that direction ratios for a line passing through points (x1, y1, z1) and (x2, y2, z2) is (x2 – x1, y2 – y1, z2 – z1).
Let’s find the direction ratios for the line AB
⇒ (r1, r2, r3) = (4 – 1, 5 – 2, 7 – 3)
⇒ (r1, r2, r3) = (3, 3, 4)
Let’s find the direction ratios for the line CD
⇒ (r4, r5, r6) = (2 – (– 4), 9 – 3, 2 – (– 6))
⇒ (r4, r5, r6) = (2 + 4, 9 – 3, 2 + 6)
⇒ (r4, r5, r6) = (6, 6, 8)
We know that the angle between the vectors with direction ratios proportional to (a1, b1, c1) and (a2, b2, c2) is given by:
Using the above formula we calculate the angle between the vectors.
Let α be the angle between the two vectors given in the problem.
∴ The angle between the given two vectors is \(0^\circ\).