Question

A rectangular park is 100m by 50 m. It is surrounded by semi-circular flower bed sall round. Find the cost of leveling the semi-circular flower bed sall 60 paise per square meter.(use π = 3.14)

Answer 1

Length of rectangular park = 100 m 

Breadth of rectangular park = 50 m 

Radius of flower bed along length of park = \(\frac{100}2\) = 50 m

Area of flower bed along length of park = \(\frac{2\timesπr^2}2\)

= \(\frac{22}7\times50\times50\) = 7850 m²

Radius of flower bed along width = \(\frac{50}2\) = 25 m

Area of flower bed along width = \(2\times\frac{22}7\times\frac{25\times25}2\) = 1962.5 m²

Total area of flower beds = 7850 + 1962.50 = 4812.50 m² 

So, 

Cost of leveling semicircular flower beds = 9812.50 ×.60 

= Rs 5887.50