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Prove that the points (3, 0), (6, 4) and (- 1, 3) are vertices of a right-angled isosceles triangle.

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Vertices of a triangle ABC are: A(3, 0), B(6, 4) and C (- 1, 3)

Since AB = AC, therefore triangle is an isosceles. 

BC2 = AB2 + AC2 

(√50)2 = (√25)2 + (√25)2 

50 = 25 + 25 

50 = 50 

Since BC2 = AB2 + AC2; therefore given triangle is right angled triangle.

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