Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
242 views
in Coordinate Geometry by (30.2k points)
closed by

Which point on x-axis is equidistant from (5, 9) and (- 4, 6)?

1 Answer

+1 vote
by (28.9k points)
selected by
 
Best answer

Since the point is on x-axis, therefore coordinate of y-axis is zero.

 Therefore the point is P(k, 0) which is equidistance from A(5, 9) and B(- 4, 6) 

PA = PB

\(\sqrt{(5 - k)^2 + 9^2}\) = \(\sqrt{(-4 - k)^2 + 6^2}\)

 On squaring both sides

(5 - k)2 + 92 = (- 4 - k)2 + 62

25 - 10k + k2 + 81 = 16 - 8k + k2 + 36

25 - 2k + 81 = 16 + 36 - 25 - 81

k = 27

Therefore coordinate is (27, 0)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...