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Calculate the volume occupied by 8.8 g of CO2 at 31.1°C and 1 bar pressure (R = 0.083 bar L K-1 mol-1).

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Number of moles of CO2 (n) = \(\frac{8.8\ g}{44\ g\ mol^{-1}} = 0.2\)

According to ideal gas equation,

pV = nRT   Or  V = \(\frac{nRT}{p}\) 

\(\frac{0.2\ mol\times0.083\ bar\ L\ K^{-1}\ mol^{-1}\times304.25\ K}{1\ bar}\) 

=5.05L

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