Vertices of a quadrilateral are A (0, 0), B(5, 5) and C(- 5, 5)
Using distance formula = \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)
Since AB = CA
Using Pythagoras theorem
BC2 = AC2 + AB2
100 = 50 + 50
100 = 100
Therefore vertices are of right isosceles triangle.