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Prove that the points (0, 0), (5, 5) and (- 5, 5) are the vertices of a right isosceles triangle.

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Vertices of a quadrilateral are A (0, 0), B(5, 5) and C(- 5, 5) 

Using distance formula = \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)

Since AB = CA 

Using Pythagoras theorem 

BC2 = AC2 + AB2 

100 = 50 + 50 

100 = 100 

Therefore vertices are of right isosceles triangle.

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