Question

Q (0, 1) is equidistant from P (5, - 3) and R (x, 6), find the values of x. Also, find the distances QR and PR.

Answer 1

Coordinates are Q(0, 1), P (5, -3) and R (x, 6), 

Using distance formula = \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)

⇒ QP = QR

\(\sqrt{(5 - 0)^2 + (-3 - 1)^2}\) = \(\sqrt{(x - 0)^2 + (6- 1)^2}\)

On squaring both sides, we get