Let the Vertices of a quadrilateral are: A(3, 0), B(4, 5), C(- 1, 4) and D(- 2, -1),
Length of side AB = \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)
Since all sides are of equal length, therefore it is a rhombus.
Area of Rhombus = \(\frac{1}2\times{d}_1\times{d}_2\) = \(\frac{1}2\times\sqrt{32}\times\sqrt{72}\) = \(\frac{1}2\times4\sqrt2\times6\sqrt2\) = 24 sq. units
