Formula:-
(iii) Three vectors \(\vec a,\,\vec b\) and \(\vec c\) are coplanar if and only if \(\vec a.(\vec b\times\vec c)=0\)
Given:-
we know that three vector \(\vec a,\vec b,\vec c\) are coplanar if their scalar triple product is zero
\([\vec a,\vec b,\vec c]\) = 0.
We have
= 1(15 – 12) + 2( – 10 + 4) + 3(6 – 3)
= 3 – 12 + 9 = 0