Question

The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per m² is Rs 4.

Answer 1

Area of rhombus = 1/2 (Product of its diagonals)

Area of each tile = (1/2 x 45 x30) cm²

= 675 cm² 

Area of 3000 tiles = (675 × 3000) cm² 

= 2025000 cm² = 202.5 m² 

The cost of polishing is Rs 4 per m^2.

Cost of polishing 202.5 m² area 

= Rs (4 × 202.5)  = Rs 810 

Thus, the cost of polishing the floor is Rs 810.