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Determine the ratio in which the straight line x - y - 2 = 0 divides the line segment joining (3, -1) and (8, 9)

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Let point be A(3, -1) and B(8, 9). 

Let the line divide the line joining the points A and B in the ratio m:n at any point C(x, y)

By section formula,

Now, substituting value of x and y in equation x - y - 2 = 0,

\(\frac{8m + 3n}{m + n} - \frac{9m - n}{m + n} - 2\) = 0

\(\frac{8m + 3n-9m + n - 2m - 2n}{m + n} \) = 0

∴ - 3m + 2n = 0

∴ \(\frac{m}n = \frac{2}3\)

∴ m:n = 2:3 

Hence, 

the line divides the line segment joining A and B in the ratio 2:3 internally.

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