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If vectors a = 2i - 3j + 5k, b = 3i - 4j + 5k and c = 5i - 3j - 2k, then the volume of the parallelepiped with conterminous edges a + b, b + c, c + a is 

A. 2

B. 1

C. –1

D. 16

1 Answer

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Best answer

Correct option is  D. 16

Now, the volume of the parallelepiped with conterminous edges  \(\vec e,\,\vec f,\,\vec g\) is given by

=5 × (-21 + 18) + 7 × (24 - 21) + 10 × (-48 + 49) 

=5 × (-3) + 7× 3 + 10 × 1

= -15 + 21 + 10

= 16

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