Question

1. Calculate the oxidation number of oxygen in OF₂ and KO₂ . 

2. When Zn rod is dipped in blue CuSO₄ solution ‘ the blue colour of CuSO₄ fades due to displacement reaction. Write the reaction and identify the following: 

(i) The substance oxidised and the substance reduced. 

(ii) The oxidant and the reductant.

Answer 1

1. OF₂ : x + (-1 × 2) = 0 

x – 2 = 0 

x = +2 

KO₂ : (+1 × 1) + 2x = 0 

1 + 2x = 0

2x = -1 

x = – \(\frac{1}{2}\)

2. Zn(s) + CuSO₄ (aq) → ZnSO₄ (aq) + Cu(s)

(i) Substance oxidised – Zn 

Substance reduced – Cu 

(ii) Oxidant-Cu 

Reductant – Zn