1. No. Zn being more reactive will displace Cu from CuSO4 . Thus Cu will be deposited on the vessel.
2. (i) NaH2 PO4
+1 +(+1 × 2) + x +(-2 × 4) = 0
1 + 2 + x – 8 = 0
x – 5 = 0
x = +5
(ii) NaHSO4
+1 + 1 + x +(-2 × 4) = 0
+1 + 1 + x – 8 = 0
x – 6 = 0
x = +6