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Calculate the oxidation number of sulphur, chromium and nitrogen in H2SO4 , Cr2O7^2- and NO3^-.

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Calculate the oxidation number of sulphur, chromium and nitrogen in H2SO4 , Cr2O72- and NO3-.

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H2SO4

(2 × +1) + x+ (4 × -2) = 0 

+2 + x – 8 = 0 

x – 6 = 0 

x = +6

Cr2O72-

2x + 7 ×-2 = -2 

2x = -2 + 14 

2x = 12 

∴ x = +6

NO3-

x + 3 × -2 = -1 

x = -1 + 5 

x = +4

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