Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
312 views
in Redox Reactions by (30.5k points)
closed by

1. Assign oxidation numbers 

(i) P in NaH2PO4

(ii) Mn in KMnO4 

(iii) B in NaBH4 

(iv) S in H2SO4 

2. Identify the oxidising and reducing agents in the following reaction: 

CuO + H2 → Cu + H2O

1 Answer

+1 vote
by (30.4k points)
selected by
 
Best answer

(i) NaH2PO4

Na+1  H+1  PO4 -2

1+2 + x- 8 = 0 

3 + x – 8 = 0 

x – 5 = 0 

x =+ 5

(ii) K+1  MnO4 -2

1+ x – 8 = 0 

x – 7 = 0 

x = +7

(iii) Na+1 BH4 +1

1 + x + 1 × 4 = 0 

x + 5 = 0 

x = -5

(iv) H2 +1 SO4 -2

2 + x – 8 = 0 

x – 6 = 0 

x = +6

2.  

CuO is the oxidising agent.

H2 is the reducing agent.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...