Sarthaks Test
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There are two cuboidal boxes as shown in the adjoining figure. Which box requires the lesser amount of material to make?

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We know that,

Total surface area of the cuboid = 2 (lh + bh + lb)

Total surface area of the cube = 6 (l)2

Total surface area of cuboid (a) = [2{(60) (40) + (40) (50) + (50) (60)}] cm2

= [2(2400 + 2000 + 3000)] cm2

= (2 × 7400) cm2

= 14800 cm2

Total surface area of cube (b) = 6 (50 cm)2 = 15000 cm2

Thus, the cuboidal box (a) will require lesser amount of material.

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