Sarthaks Test
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A road roller takes 750 complete revolutions to move once over to level a road. Find the area of the road if the diameter of a road roller is 84 cm and length is 1 m.

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In one revolution, the roller will cover an area equal to its lateral surface area. Thus, in 1 revolution, area of the road covered = 2πrh

= 2 x (22/7) x 42 cm x 1cm

= 2 x (2/7) x 42/100m x 1 m

= (264/100) m2

In 750 revolutions, area of the road covered

= {750 x (264/100)} m2

= 1980 m2


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