In one revolution, the roller will cover an area equal to its lateral surface area. Thus, in 1 revolution, area of the road covered = 2πrh
= 2 x (22/7) x 42 cm x 1cm
= 2 x (2/7) x 42/100m x 1 m
= (264/100) m2
In 750 revolutions, area of the road covered
= {750 x (264/100)} m2
= 1980 m2