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+1 vote
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in Oscillations by (35.6k points)
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A particle executes simple harmonic motion according to the equation x = 5sin(\(\frac{2π}{3}\)t)

1. find the period of the oscillation

2. What is the minimum time required for the particle to move between two points 2.5cm on either side of the mean position?

1 Answer

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by (33.8k points)
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Best answer

1. x = 5 sin(\(\frac{2π}{3}\)t), when we compare this equation with standard S.H.M, x = a sin wt.

We get wt = \(\frac{2π}{3}\)t

2. y = a sin wt

2.5 = 5 sin w × t

Time taken to travel 2.5 from the mean position is 0.25 sec. Hence time taken to travel 2.5 cm on either side of the mean position is 0.5 sec.

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