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When a pebble is dropped to the surface of water, certain waves are formed on the water surface.

1. What type of wave is it?

2. Is it a progressive wave? Explain?

3. The equation for such a wave is y = 4sinπ (2t – 0.01x). where ‘y’ and ‘x’ are in cm. and ‘t’ in sec. find its 

  • Amplitude
  • Wavelength
  • initial phase
  • Frequency

1 Answer

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Best answer

1. Transverse wave.

2. It is a progressive wave. It moves from one point to another point.

3. y = 4sinπ(2t – 0.01x)

y = 4 sin (2πt-0.01πx)

= -4 sin (0.01 πx – 2πt)

Comparing with standard wave equation, y = A sin (kx – ωt), we get

  • Amplitude A = 4 m
  • Kx = 0.01 × πx
    \(\frac{2π}{λ}\)x = 0.01 πx, λ = 200m
  • Initial phase = 0
  • ωt = 2 πt, 2 π f t = 2 πt, f = 1 Hz.

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