Question

A stone droped from the top of a tower of height 300m high splashes into the water of a pond near the base of the tower. When is the splash heard at the top. Given that the speed of sound in air is 340ms^-1? (g = 9.8ms^-2)

Answer 1

Time after which the splash is heard at the top is equal to the sum of the time t₁ taken by the stone to fall down and the time t₂ taken by the sound to travel from bottom to top.

Using S = ut + \(\frac{1}{2}\) at², we 9et S = \(\frac{1}{2}\)gt₁²

(∵ u = 0 and a =g)