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It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?

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Probability that two students are not having same birthday P (bar E) = 0.992

Probability that two students are having same birthday P (E) = 1 − P (bar E)

= 1 − 0.992

= 0.008

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