Sample space = 36
(i) n(E) = 5
∴ P = \(\frac{n(E)}{n(S)}\) = \(\frac{5}{36}\)
(ii) n(E) = 6
∴ P = \(\frac{n(E)}{n(S)}\) = \(\frac{5}{36}\) = \(\frac{1}{6}\)
(iii) n(E) = 3
∴ P = \(\frac{n(E)}{n(S)}\) = \(\frac{3}{36}\) = \(\frac{1}{12}\)
(iv) P = \(\frac{n(E)}{n(S)}\) = \(\frac{3}{36}\) = \(\frac{1}{12}\)
(v) P = \(\frac{n(E)}{n(S)}\) = \(\frac{6}{36}\) = \(\frac{1}{6}\)
(vi) P = \(\frac{n(E)}{n(S)}\) = \(\frac{3}{36}\) = \(\frac{1}{12}\)
(vii) P = \(\frac{n(E)}{n(S)}\) = \(\frac{11}{36}\)
(viii) Number of event with sum 9 or 11 = 6
∴ Number of events of not getting a sum of either 9 or 11 = 36 – 6 = 30
P = \(\frac{n(E)}{n(S)}\) = \(\frac{30}{36}\) = \(\frac{5}{6}\)
(ix) P = \(\frac{n(E)}{n(S)}\) = \(\frac{10}{36}\) = \(\frac{5}{18}\)
(x) P = \(\frac{n(E)}{n(S)}\) = \(\frac{15}{36}\) = \(\frac{5}{12}\)
(xi) P = \(\frac{n(E)}{n(S)}\) = \(\frac{15}{36}\) = \(\frac{5}{12}\)
(xii) P = \(\frac{n(E)}{n(S)}\) = \(\frac{11}{36}\)
(xiii) P = \(\frac{n(E)}{n(S)}\) = \(\frac{25}{36}\)