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Three coins are tossed together. Find the probability of getting: 

(i) exactly two heads 

(ii) at most two heads 

(iii) at least one head and one tail. 

(iv) no tails

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Sample space, n(S) = 8 

(i) p = \(\frac{n(E)}{n(S)}\)\(\frac{3}{8}\)

(ii)  p = \(\frac{n(E)}{n(S)}\)\(\frac{4}{8}\) = \(\frac{1}{2}\)

(iii)  p = \(\frac{n(E)}{n(S)}\)\(\frac{6}{8}\) = \(\frac{3}{4}\) 

(iv)  p = \(\frac{n(E)}{n(S)}\)\(\frac{1}{8}\) 

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