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A black die and a white die are thrown at the same time. Write all the possible outcomes. What is the probability? 

(i) that the sum of the two numbers that turn up is 8? 

(ii) of obtaining a total of 6? 

(iii) of obtaining a total of 10? 

(iv) of obtaining the same number on both dice? 

(v) of obtaining a total more than 9? 

(vi) that the sum of the two numbers appearing on the top of the dice is 13? 

(vii) that the sum of the numbers appearing on the top of the dice is less that or equal to 12? 

(viii) that the product of numbers appearing on the top of the two dice is 2. 

(ix) that the difference of the numbers appearing on the top of the two dice is 2.

1 Answer

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Sample space, n(S) = 36 

(i) N(E) = 5

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{5}{36}\)

(ii) n(E) = 5

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{5}{36}\)

(iii) n(E) = 3

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{3}{36}\) = \(\frac{1}{12}\)

(iv) n(E) = 6

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{6}{36}\) = \(\frac{1}{6}\)

(v) n(E) = 6

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{6}{36}\) = \(\frac{1}{6}\)

(vi) The maximum sum is 12. So, getting a sum of number appearing on the top of the two dice as 13 is an impossible event. 

∴ Probability, P(E) = 0 

(vii) n(E) = 36

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{36}{36}\) = 1

(viii) n(E) = 2

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{2}{36}\) = \(\frac{1}{18}\)

(ix) n(E) = 8

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{8}{36}\) = \(\frac{2}{9}\)

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