Total number of possible outcomes, n(S) = 5
(i) Number of events of drawing a queen,
n(E) = 1
∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{1}{5}\)
(ii) If a king is drawn first and put aside, total number of remaining cards, n(S) = 4
a) Probability that second card is ace,
P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{1}{4}\)
b) Since there was only a single king and when it is put aside, then
n(E) = 0
∴ P(E) = \(\frac{n(E)}{n(S)}\) = 0