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Five cards – ten, jack, queen, king and an ace of diamonds are shuffled face downwards. One card is picked at random. 

(i) What is the probability that the card is a queen? 

(ii) If a king is drawn first and put aside, what is the probability that the second card picked up is the 

(a) ace? 

(b) king?

1 Answer

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Best answer

Total number of possible outcomes, n(S) = 5 

(i) Number of events of drawing a queen, 

n(E) = 1

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{1}{5}\)

(ii) If a king is drawn first and put aside, total number of remaining cards, n(S) = 4 

a) Probability that second card is ace,

P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{1}{4}\)

b) Since there was only a single king and when it is put aside, then

n(E) = 0

∴ P(E) = \(\frac{n(E)}{n(S)}\) = 0

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