Total number of possible outcomes, n(S) = 89
(i) Number of favorable outcomes of getting a two digit number = 81
∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{81}{89}\)
(ii) Number of favorable outcomes of getting a perfect square = 8
∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{8}{89}\)