Sarthaks Test
0 votes
1.6k views
in Physics by (8.6k points)
edited by

A raindrop of mass 1.00 g falling from a height of 1 km hits the ground with a speed of 50 m s–1. Calculate 

(a) the loss of P.E. of the drop. 

(b) the gain in K.E. of the drop. 

(c) Is the gain in K.E. equal to loss of P.E.? If not why. 

Take g = 10 m s-2

1 Answer

0 votes
by (13.6k points)
selected by
 
Best answer

(a) Loss of PE = mgh = 1 x 10-3 x 10 x 10-3 = 10J

(b) Gain in KE = (1/2)mv2 = (1/2) x 10-3 x 2500 = 1.25J

(c) No, because a part of PE is used up in doing work against the viscous drag of air.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...