Total number of possible outcomes, n(S) = 52 – 2 – 2 – 2 – 2 = 44
(i) Number of favorable outcomes,
n(E) = 2
∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{2}{44}\) = \(\frac{1}{22}\)
(ii) Number of favorable outcomes, n(E) = 26 – 8 = 18
∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{18}{44}\) = \(\frac{9}{22}\)
(iii) Number of favorable outcomes,
n(E) = 2
∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{2}{44}\) = \(\frac{1}{22}\)
(iv) Number of favorable outcomes,
n(E) = 6
∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{6}{44}\) = \(\frac{3}{22}\)