Total number of possible outcomes, n(S) = 52 – 3 = 49
(i) Number of favorable outcomes,
n(E) = 13
∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{13}{49}\)
(ii) Number of favorable outcomes, n(E) = 4 – 1 = 3
∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{3}{49}\)
(iii) Number of favorable outcomes, n(E) = 13 – 3 = 10
∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{10}{49}\)