Total number of possible outcomes, n(S) = 30
(i) Number of favorable outcomes of numbers divisible by 3,
n(E) = 10
∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{10}{30}\) = \(\frac{1}{3}\)
Probability of getting a number not divisible by 3 = 1 – P(E)
= 1 - \(\frac{1}{3}\) = \(\frac{2}{3}\)
(ii) Number of favorable outcomes,
n(E) = 6
∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{6}{30}\) = \(\frac{1}{5}\)
(iii) Number of favorable outcomes of getting a perfect square,
n(E) = 5
= 1 - \(\frac{1}{6}\) = \(\frac{5}{6}\)