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A piggy bank contains hundred 50 paise coins, fifty Rs.1 coins, twenty Rs.2 coins and ten Rs.5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, find the probability that the coin which fell 

(i) will be a 50 paise win 

(ii) will be of value more than Rs.1 

(iii) will be of value less than Rs.5 

(iv) will be a Rs.1 or Rs.2 coin

1 Answer

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Best answer

Total number of possible outcomes, n(S) = 100 + 50 + 20 + 10 = 180 

(i) Number of favorable outcomes, 

n(E) = 100

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{100}{180}\) = \(\frac{5}{9}\)

(ii) Number of favorable outcomes, n(E) = 20 + 10 = 30

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{30}{180}\) = \(\frac{1}{6}\)

(iii) Number of favorable outcomes, n(E) = 100 + 50 + 20 = 170

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{170}{180}\) = \(\frac{17}{18}\)

(iv) Number of favorable outcomes, n(E) = 50 + 20 = 70

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{70}{180}\) = \(\frac{7}{18}\)

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