Total number of possible outcomes, n(S) = 100 + 50 + 20 + 10 = 180
(i) Number of favorable outcomes,
n(E) = 100
∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{100}{180}\) = \(\frac{5}{9}\)
(ii) Number of favorable outcomes, n(E) = 20 + 10 = 30
∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{30}{180}\) = \(\frac{1}{6}\)
(iii) Number of favorable outcomes, n(E) = 100 + 50 + 20 = 170
∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{170}{180}\) = \(\frac{17}{18}\)
(iv) Number of favorable outcomes, n(E) = 50 + 20 = 70
∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{70}{180}\) = \(\frac{7}{18}\)