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A die is thrown once. What is the probability of getting a prime number?

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Total numbers of elementary events are: 6 being a dice having six faces

Let E be the event of getting a prime number 

Total favorable outcomes are: 1, 2, 3, 5 

Total number of favorable events = 4 

P (prime number) = P (E) = \(\frac{4}6\) = \(\frac{2}3\)

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