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Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn bears a number which is a multiple of 3?

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Total numbers of elementary events are = 20 

Let E be the event of drawing a multiple of 3 

The favorable outcomes are: 3, 6, 9, 12, 15, 18 

Total numbers of favorable outcomes are = 6 

P (multiple of 3) = P (E) = \(\frac{6}{20}\) = \(\frac{3}{10}\)

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